10(3x^2-13x)=-40

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Solution for 10(3x^2-13x)=-40 equation:


Simplifying
10(3x2 + -13x) = -40

Reorder the terms:
10(-13x + 3x2) = -40
(-13x * 10 + 3x2 * 10) = -40
(-130x + 30x2) = -40

Solving
-130x + 30x2 = -40

Solving for variable 'x'.

Reorder the terms:
40 + -130x + 30x2 = -40 + 40

Combine like terms: -40 + 40 = 0
40 + -130x + 30x2 = 0

Factor out the Greatest Common Factor (GCF), '10'.
10(4 + -13x + 3x2) = 0

Factor a trinomial.
10((1 + -3x)(4 + -1x)) = 0

Ignore the factor 10.

Subproblem 1

Set the factor '(1 + -3x)' equal to zero and attempt to solve: Simplifying 1 + -3x = 0 Solving 1 + -3x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -3x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -3x = 0 + -1 -3x = 0 + -1 Combine like terms: 0 + -1 = -1 -3x = -1 Divide each side by '-3'. x = 0.3333333333 Simplifying x = 0.3333333333

Subproblem 2

Set the factor '(4 + -1x)' equal to zero and attempt to solve: Simplifying 4 + -1x = 0 Solving 4 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1x = 0 + -4 -1x = 0 + -4 Combine like terms: 0 + -4 = -4 -1x = -4 Divide each side by '-1'. x = 4 Simplifying x = 4

Solution

x = {0.3333333333, 4}

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